An equilateral triangle is constructed between two parallel lines $\sqrt{3}x+y-6=0$ and $\sqrt{3}x+y+9=0$ with base on one and vertex on the other. Then the area of triangle is

• A

  $\frac{200}{\sqrt{3}}$

• B

  $\frac{225}{4\sqrt{3}}$

• C

  $\frac{225}{\sqrt{3}}$

• D

  $\frac{200}{4\sqrt{3}}$