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 Evaluate 1cosxcosx(1+cosx)dx

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a
log⁡|sec⁡x+tan⁡x|−2tan⁡x/2+C
b
log⁡|sec⁡x-tan⁡x|−2tan⁡x/2+C
c
sec⁡xtanx−2tan⁡x/2+C
d
None of these

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detailed solution

Correct option is A

Let I=∫1−cos⁡xcos⁡x(1+cos⁡x)dx  Let cosx=y, then 1−cos⁡xcos⁡x(1+cos⁡x)=1−yy(1+y)=1y−21+y=1cos⁡x−21+cos⁡x∴ l=∫1−cos⁡xcos⁡x(1+cos⁡x)dx=∫1cos⁡xdx−∫21+cos⁡xdx=∫sec⁡xdx−∫22cos2⁡x2dx=∫sec⁡x−∫sec2⁡x2dx=log⁡|sec⁡x+tan⁡x|−2tan⁡x2+C


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