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Q.

Evaluate ∫cos3⁡xsin⁡xdx

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a

=23sin3/2⁡x−27sin5/2⁡x+c

b

=27sin3/2⁡x−23sin7/2⁡x+c

c

=23sin3/2⁡x−27sin7/2⁡x+c

d

=23sin7/2⁡x−27sin5/2⁡x+c

answer is C.

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Detailed Solution

∫cos2xsin⁡x cosxdx∫1-sin2xsin⁡x  cosx dx∫sin12x-sin52x cosx dxsin32x32-sin72x72+c=z3/23/2−z7/27/2+c=23z3/2−27z7/2+c=23sin3/2⁡x−27sin7/2⁡x+c
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