Download the app

Questions  

 Evaluate 04πdxcos2x2+tan2x

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
b
22π
c
32π
d
42π

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is B

∫04π sec2⁡x2+tan2⁡xdx=2∫02π sec2⁡xdx2+tan2⁡x   using formula∫02af(x)dx=2∫0af(x) dx if f(2a-x)=f(x)=4∫0π sec2⁡x2+tan2⁡xdx=8∫0π2 sec2⁡xdx2+tan2⁡x=8∫0π/2 d(tan⁡x)2+tan2⁡x=82tan−1⁡tan⁡x20π/2=82π2−0=22π


Similar Questions

If mn,m,nN then the value of 02πcosmx cosnxdx is


whats app icon
phone icon