Questions
detailed solution
Correct option is B
∫04π sec2x2+tan2xdx=2∫02π sec2xdx2+tan2x using formula∫02af(x)dx=2∫0af(x) dx if f(2a-x)=f(x)=4∫0π sec2x2+tan2xdx=8∫0π2 sec2xdx2+tan2x=8∫0π/2 d(tanx)2+tan2x=82tan−1tanx20π/2=82π2−0=22πSimilar Questions
If then the value of is
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