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a
logsecx+tan2x2+c
b
log tanx+tan2x2+c
c
logsecx+sec2x2+c
d
None of these
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Correct option is B
Here, the power of sin x is -1 and that of cos x is -3. Since the sum of powers of sin x and cos x is -4, which is even and negative I=∫dxsinxcos3x=∫sec4xdxtanx=∫1+tan2xsec2xdxtanxLet tan x = z. Then, sec2 xdx = dz. Therefore,I=∫1+z2zdz=∫1z+zdz=log|z|+z22+c=logtanx∣+tan2x2+cSimilar Questions
is equal to
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