First slide
Methods of integration
Question

 Evaluate dxsinxcos3x

Moderate
Solution

Here, the power of sin x is -1 and that of cos x is -3.  

Since the sum of powers of sin x and cos x is -4, which is even and negative 

I=dxsinxcos3x=sec4xdxtanx=1+tan2xsec2xdxtanx

Let tan x = z. Then, sec2 xdx = dz. Therefore,I=1+z2zdz=1z+zdz=log|z|+z22+c=logtanx+tan2x2+c

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