Evaluate ∫dxsinxcos3x
logsecx+tan2x2+c
log tanx+tan2x2+c
logsecx+sec2x2+c
None of these
Here, the power of sin x is -1 and that of cos x is -3.
Since the sum of powers of sin x and cos x is -4, which is even and negative
I=∫dxsinxcos3x=∫sec4xdxtanx=∫1+tan2xsec2xdxtanx
Let tan x = z. Then, sec2 xdx = dz. Therefore,I=∫1+z2zdz=∫1z+zdz=log|z|+z22+c=logtanx∣+tan2x2+c