Evaluate ∫dx(2x−7)(x−3)(x−4)
sec−1(2x−7)+c
12sec−1(2x−7)+c
17sec−1(2x−7)+c
None of these
I=∫dx(2x−7)(x−3)(x−4)=∫dx(2x−7)x2−7x+12=12∫2dx(2x−7)(2x−7)2−1=12sec−1(2x−7)+c ∵ ∫dttt2-1=sec-1(t)+c