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Questions  

 Evaluate e2xsin3xdx 

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a
e2x13(3sin⁡3x−2cos⁡3x)+c
b
e2x13(2sin⁡3x+3cos⁡3x)+c
c
e2x13(2sin⁡3x−3cos⁡3x)+c
d
None of these

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detailed solution

Correct option is C

∫e2xsin⁡3xdx=e2x22+32(2sin⁡3x−3cos⁡3x)+c                          =e2x13(2sin⁡3x−3cos⁡3x)+c  using the formula ∫eaxsin(bx+c) dx =eaxa2+b2asin(bx+c)-bcos(bx+c)


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