First slide
Methods of integration
Question

 Evaluate ex(1+x)cos2xexdx

Easy
Solution

 Let z=xex. Then dz=1ex+xexdx=ex1+xdx .  

Thus,     ex(1+x)cos2xexdx=dzcos2z                                             =sec2zdz                                             =tanz+c=tanxex+c

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