Evaluate ∫$$e2x$$−$$12xdx$$

Correct option is 2log⁡ex+e−x+C

Questions

$Evaluate \int \frac{e^{2 x} - 1}{2 x} d x$

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log⁡ex-e−x+C

log⁡ex+e−x+C

12log⁡ex+e−x+C

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detailed solution

Correct option is B

I=∫e2x−1e2x+1dx=∫(e2x-1)ex(e2x+1)exdx=∫ex−e−xex+e−xdx Let ex+e−x=t or ex−e−xdx=dt ∴ I=∫dtt =log⁡|t|+C =log⁡ex+e−x+C

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Evaluate ∫e2x−12xdx

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$Evaluate \int \frac{e^{2 x} - 1}{2 x} d x$