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$Evaluate \int e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x$

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-1xex+C

1x2ex+C

1xex+C

None of these

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detailed solution

Correct option is C

∫ex1x−1x2dx=∫ex1x+1x′dx=1xex+C [ formula ∫exf(x)+f′(x)dx=exf(x)+C ]

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Evaluate ∫ex1x−1x2dx

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$Evaluate \int e^{x} (\frac{1}{x} - \frac{1}{x^{2}}) d x$