First slide
Introduction to limits
Question

Evaluatelimn{12tanx2+122tanx22+....+12ntanx2n}

Moderate
Solution

limn{12tanx2+122tanx22+....+12ntanx2n}  = limn{cotx+(cotx+12tanx2+122tanx22+....+12ntanx2n)}limn{cotx+(12cotx2+122tanx22)+....+12ntanx2n} (cotx+12tanx2=12cotx2) Proceeding like this we get =limn{cotx+12ncotx2n} =cotx+limn(x/2ntanx2n.1x)=cotx+1x

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