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 Evaluate π/2π/2logasinθa+sinθdθ,a>0.

 

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detailed solution

Correct option is A

f(θ)=log⁡a−sin⁡θa+sin⁡θf(−θ)=log⁡a+sin⁡θa−sin⁡θ=−log⁡a−sin⁡θa+sin⁡θ=−f(θ)since  the integrand is an odd function the given integral is zero.


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