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 Evaluate secxsecx+tanxdx . 

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a
=tan⁡x−sec⁡x+c
b
=tan⁡x+sec⁡x+c
c
=-tan⁡x−sec⁡x+c
d
=sec⁡x-tan x+c

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detailed solution

Correct option is A

∫sec⁡xsec⁡x+tan⁡xdx=∫sec⁡x(sec⁡x−tan⁡x)(sec⁡x+tan⁡x)(sec⁡x−tan⁡x)dx=∫sec2⁡x−sec⁡xtan⁡xsec2⁡x−tan2⁡xdx=∫sec2⁡xdx−∫sec⁡xtan⁡xdx=tan⁡x−sec⁡x+c


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