First slide
Methods of integration
Question

 Evaluate sin(logx)dx

Moderate
Solution

 Let I=sin (logx)dx  Let logx=t . Then x=et or dx=etdt . Thus.  I=sint etdt=et2(sintcost)+c using the formula  eaxsin(bx+c)=eaxa2+b2[asin(bx+c)-bcos(bx+c)] Hence, sin(logx)dx=x2[sin(logx)cos(logx)]+c

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