Evaluate ∫13sinx+cosxdx
12logtanx2+π6+c
12logtanx2+π12+c
12logtanx2+c
None of these
Let 3=rsinθ and 1=rcosθ Then r=(3)2+12=2 and tanθ=31 or θ=π3
∴ ∫13sinx+cosxdx =∫1rsinθsinx+rcosθcosxdx =1r∫1cos(x−θ)dx=1r∫sec(x−θ)dx
=1rlogtanπ4+x2−θ2+c =12logtanπ4+x2−π6+c =12logtanx2+π12+c