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 Evaluate π/6π/3(sinx)dx(sinx)+(cosx)

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a
π2
b
π12
c
π3
d
π4

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detailed solution

Correct option is B

Given integral I=∫π/6π/3 (sin⁡x)dx(sin⁡x)+(cos⁡x)------(1) or I=∫π/6π/3 (cos⁡x)dx(cos⁡x)+(sin⁡x) Replacing x by π2−x---(2)Adding equations (l ) and (2), we get2I=∫π/6π/3 (sin⁡x)+(cos⁡x)(cos⁡x)+(sin⁡x)dx     =∫π/6π/3 dx=[x]π/6π/3=π/3−π/6=π/6⇒ I=π/12


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