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 Evaluate sin3xdx

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a
−34cos⁡x+cos⁡3x4+C
b
−34cos⁡x+cos⁡3x12+C
c
34cos⁡x-cos⁡3x12+C
d
None of these

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detailed solution

Correct option is B

sin⁡3x=3sin⁡x−4sin3⁡xsin3⁡x=3sin⁡x−sin⁡3x4∫sin3⁡dx=∫3sin⁡x−sin⁡3x4dx=34∫sin⁡xdx−14∫sin⁡3xdx=34(−cos⁡x)−14−cos⁡3x3+C=−34cos⁡x+cos⁡3x12+C


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