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a
212
b
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c
192
d
172
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Correct option is A
∫016π/3 |sinx|dx=∫05π |sinx|dx+∫5π5π+π/3 |sinx|dx =5∫0π |sinx|dx+∫0π/3 |sinx|dx[∵|sinx| is periodic with period π=5∫0π sinxdx+∫0π/3 sinxdx =5[−cosx]0π+[−cosx]0π3 =5×2+−12+1=212Similar Questions
The value of is
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