First slide
Evaluation of definite integrals
Question

 Evaluate 016π/3|sinx|dx

Moderate
Solution

016π/3|sinx|dx=05π|sinx|dx+5π5π+π/3|sinx|dx =50π|sinx|dx+0π/3|sinx|dx[|sinx| is periodic with period π=50πsinxdx+0π/3sinxdx =5[cosx]0π+[cosx]0π3 =5×2+12+1=212

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