First slide
Methods of integration
Question

 Evaluate tanxa+btan2xdx

Moderate
Solution

I=tanxa+btan2xdx=sinxcosxa+bsin2xcos2xdx=sinxcosxacos2x+bsin2xdx=12sin2xacos2x+bsin2xdx Put acos2x+bsin2x=t (ba)sin2xdx=dt l=12(ba)dtt      =12(ba)loge|t|+C      =12(ba)logacos2x+bsin2x+C

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