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 Evaluate tan4xdx

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a
sec3⁡x3−tan⁡x+C
b
sec3⁡x3−tan⁡x+x+C
c
tan3⁡x3+tan⁡x+x+C
d
tan3⁡x3−tan⁡x+x+C

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detailed solution

Correct option is D

∫tan4⁡xdx=∫tan2⁡xtan2⁡xdx=∫tan2⁡xsec2⁡x−1dx∫tan2⁡xsec2⁡xdx−∫tan2⁡xdx=tan3⁡x3−∫sec2⁡x−1dx                                                          =tan3⁡x3−tan⁡x+x+C


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