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Questions  

 Evaluate 3x2tan1xxsec21xdx

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a
x3tan⁡1x+c
b
x2tan⁡1x+c
c
6xtan⁡1x+c
d
none of these

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detailed solution

Correct option is A

=∫3x2tan⁡1x−xsec2⁡1xdx=∫3x2tan⁡1xdx−∫xsec2⁡1xdx (apply integration by parts only for 1st integrand)=tan⁡1xx3−∫sec2⁡1x−1x2x3dx−∫xsec2⁡1xdx=x3tan⁡1x+c


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