Evaluate ∫0100 (x−[x])dx (where [ re- presents the greatest integer function).
50
100
200
150
x−[x]={x} has period 1 . Thus, ∫0100 (x−[x])dx=100∫01 {x}dx =100∫01 xdx(∵ for x∈(0,1),(x}=x) =1002x201=50