Evaluate ∫x2+2x+5dx
12(x+1)x2+2x+5+2sinh-1x+C
12(x+1)x2+2x+5+2cosh-1x+C
12(x+1)x2+2x+5-2sinh-1x+C
none of these
∫x2+2x+5dx=∫(x+1)2+4dx ∫a2+x2dx=x2a2+x2+a22sinh-1x+c ∫(x+1)2+4dx=12(x+1)(x+1)2+22+12⋅(2)2sinh-1x+C =12(x+1)x2+2x+5+2sinh-1x+C