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 Evaluate 1(x3)x+1dx

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a
12log⁡x+1−2x+1+2+C
b
12log⁡x+1+2x+1-2+C
c
14log⁡x+1−2x+1+2+C
d
None of these

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detailed solution

Correct option is A

Let I=∫1(x−3)x+1dx  Let x+1=t2 or dx=2tdt ∴ I=∫1t2−1−32tt2dt=2∫dtt2−22=2×12(2)log⁡t−2t+2+C=12log⁡x+1−2x+1+2+C


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