Evaluate ∫$$1x2$$−$$x+1dx$$

Correct option is 323tan−1⁡2x−13+C

Questions

$Evaluate \int \frac{1}{x^{2} - x + 1} d x$

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23tan−1⁡x−13+C

13tan−1⁡2x−13+C

23tan−1⁡2x−13+C

-13tan−1⁡2x−13+C

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detailed solution

Correct option is C

∫1x2−x+1dx=∫1(x−1/2)2+3/4dx=∫1(x−1/2)2+(3/2)2dx=13/2tan−1⁡x−1/23/2+C=23tan−1⁡2x−13+C

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Evaluate ∫1x2−x+1dx

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$Evaluate \int \frac{1}{x^{2} - x + 1} d x$