First slide
Methods of integration
Question

 Evaluate 2xx2+1x2+2dx

Easy
Solution

 Let I=2xx2+1x2+2dx 

 Putting x2=t and 2xdx=dt, we get 

 I=dt(t+1)(t+2)=1t+11t+2dt=log|t+1|log|t+2|+C=logx2+1logx2+2+C

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App