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 Evaluate 4x+1x2+3x+2dx

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a
2log⁡x2+3x+2−52log⁡x+1x+2+C
b
2log⁡x2+3x+2−5log⁡2x+12x+2+C
c
2log⁡x2+3x+2−5log⁡x+1x+2+C
d
None of these

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detailed solution

Correct option is C

I=∫4x+1x2+3x+2dx=∫2(2x+3)−5x2+3x+2dx=2∫2x+3x2+3x+2dx−5∫1x2+3x+2dx=2log⁡x2+3x+2∣−5∫1x2+3x+(94)−(94)+2dx=2log⁡x2+3x+2−5∫1(x+32)2−(12)2dx=2log⁡x2+3x+2−512(12)logx+32−12x+32+12+C=2log⁡x2+3x+2−5log⁡x+1x+2+C


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