An even polynomial function f(x) satisfies a relation f2x1-f12x+f16x2y=f-2-f4xy∀x,y∈R-0 and f4 =-255, f0=1. Then the value of f(2) is________
We have f2x- f2xf12x+f16x2y=f-2-f4xyReplacing y by 18x2, we getf2x-f2x12x+f2=f-2-f12x∴ f2x+f12x=f2xf12x As fx is even∴ f2x=1±2xnor fx=1±xn
Now, f4=1±4n=-255 Given
Taking negative sign, we get 256=4n or n=4
Hence, fx=1-x4, which is an even function
Therefore, f2=-15.