Events A, B, C are mutually exclusive events such that P(A)=3x+13, P(B)=1−x4 and P(C)=1−2x2 . The set of possible values of x are in the interval

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12, 23

13, 133

[0, 1]

13, 12

answer is D.

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Detailed Solution

Using 0≤P(A)≤1, 0≤P(B)≤1 ,0≤P(C)≤1, 0≤P(A)+P(B)+P(C)≤1We havex∈13,12

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