Events A and C are independent. If the probabilities relatingA,B, and C are P(A)=1/5,P(B)=1/6;P(A∩C)=120P(B∪C)=3/8. Then

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events B and C arc independent

events B and C arc mutually exclusive

events B and C arc neither independent nor mutually exclusive

events B and C are equiprobable

answer is A.

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Detailed Solution

P(A∩C)=P(A)P(C) or 120=15P(C) or P(C)=14now,P(B∪C)=16+14−P(B∩C)P(B∩C)=512−38=124=P(B)P(C) Therefore, B and C are independent.

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