In the expansion of (a + b)n, if two consecutive terms are equal, then which of the following is/are always integer?
(n+1)ba+b
(n+1)aa+b
naa−b
naa+b
We have (a + b)n
Tr+1Tr=n−r+1r⋅ba=1
∴ (n+1)b−br=ar
∴ r=(n+1)ba+b is integer
Also, considering (b + a)n.
Tr+1Tr=n−r+1r⋅ab=1
∴ r=(n+1)aa+b is integer