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Questions  

In the expansion of (x + a)n , if the sum of odd terms be A and the sum of even terms be B, then value of (x2  a2 )n is

a
AB
b
2AB
c
4AB
d
A2−B2

detailed solution

Correct option is D

We have (x+a)n=A+B and (x−a)n=A−B ∴x2−a2n=(x+a)n(x−a)n=(A+B)(A−B)=A2−B2.

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