Q.

In the expansion of x2+1+1x2n,n∈N

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

number of terms is 2n + 1

b

coefficient of constant term is 2n-1

c

coefficient of x2n-2 is n

d

coefficient of x2 in n

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

x2+1+1x2=nC0+nC1x2+1x2+nC2x2+1x22+⋯+nCnx2+1x2nThis contain search of the term x0,x2,x4,…x2n,x−2,x−4,…x−2ncoefficient of constant term =nC0+ nC2(2)+ nC4 4C2+ nC6 6C3+…≠2n−1coefficient of x2n−2 in nCn−1=ncoefficient of x2 is  nC1+ nC3 3C1+ nC5 5C2+…>n
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon