Q.
In the expansion of x2+1+1x2n,n∈N
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a
number of terms is 2n + 1
b
coefficient of constant term is 2n-1
c
coefficient of x2n-2 is n
d
coefficient of x2 in n
answer is A.
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Detailed Solution
x2+1+1x2=nC0+nC1x2+1x2+nC2x2+1x22+⋯+nCnx2+1x2nThis contain search of the term x0,x2,x4,…x2n,x−2,x−4,…x−2ncoefficient of constant term =nC0+ nC2(2)+ nC4 4C2+ nC6 6C3+…≠2n−1coefficient of x2n−2 in nCn−1=ncoefficient of x2 is nC1+ nC3 3C1+ nC5 5C2+…>n
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