In the expansion of x2+1+1x2n,n∈N

x2+1+1x2=nC0+nC1x2+1x2+nC2x2+1x22+⋯+nCnx2+1x2nThis contain search of the term x0,x2,x4,…x2n,x−2,x−4,…x−2ncoefficient of constant term =nC0+ nC2(2)+ nC4 4C2+ nC6 6C3+…≠2n−1coefficient of x2n−2 in nCn−1=ncoefficient of x2 is  nC1+ nC3 3C1+ nC5 5C2+…>n