The exponent of power of x occurring in the 7th term of expansion of (3x2−87x)9 is
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a
3
b
−3
c
5
d
−5
answer is B.
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Detailed Solution
Given expansion is(3x2−87x)9 We have general term in the expansion (x+a)n (∴ Tr+1= nCr xn−r (a)r be the expansion of (x+a)n) 7th term of expansionT7=T6+1= 9C6(3x2)9−6 (−87x)6 T7=T6+1= 9C6(32)3(−87)6x−3 (∴xaxb=xa−b) The exponent of power of x be the −3 (power of x )