The expression cos2⁡(α+β)+cos2⁡(α−β)−cos⁡2α.cos2β is

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independent of α

independent of β

independent of α and β

dependent on α and β

answer is A.

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Detailed Solution

cos2⁡(α+β)+cos2⁡(α−β)−cos⁡2αcos⁡2β =cos2⁡(α+β)+1−sin2⁡(α−β)−cos⁡2αcos⁡2β =1+cos⁡2αcos⁡2β−cos⁡2αcos⁡2β =1

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