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The expression ${[\frac{1 + \sin \frac{π}{8} + icos \frac{π}{8}}{1 + \sin \frac{π}{8} - icos \frac{π}{8}}]}^{8} =$

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Correct option is B

Let sin⁡π8+icos⁡π8=z⇒1+sin⁡π8+icos⁡π81+sin⁡π8−icos⁡π88=1+z1+1z8=z8=sin⁡π8+icos⁡π88=cos⁡π2−π8+isin⁡π2−π88=cos⁡3π8+isin⁡3π88=cos⁡3π=−1

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The expression1+sin⁡π8+icos⁡π81+sin⁡π8−icos⁡π88=

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The expression ${[\frac{1 + \sin \frac{π}{8} + icos \frac{π}{8}}{1 + \sin \frac{π}{8} - icos \frac{π}{8}}]}^{8} =$