The expression 3sin432π−α+sin4(3π+α)−2sin612π+α+sin6(5π−α) is equal to
0
1
3
none of these
3sin432π−α+sin4(3π+α)−2sin612π+α+sin6(5π−α)
=3cos4α+sin4α−2cos6α+sin6α=31−2sin2αcos2α−2sin2α+cos2α3−3sin2αcos2αsin2α+cos2α
=31−2sin2αcos2α−21−3sin2αcos2α=1