First slide
Trigonometric Identities
Question

The expression  3sin432πα+sin4(3π+α)2sin612π+α+sin6(5πα) is equal to

Moderate
Solution

3sin432πα+sin4(3π+α)2sin612π+α+sin6(5πα)

=3cos4α+sin4α2cos6α+sin6α=312sin2αcos2α2sin2α+cos2α33sin2αcos2αsin2α+cos2α

=312sin2αcos2α213sin2αcos2α=1

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