The expression tan4⁡x+2tan2⁡x+1cos2⁡x, when x=π/12, can be equal to

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4(2−3)

4(2+1)

16cos2⁡π/12

16sin2⁡π/12

answer is A.

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Detailed Solution

y=1+tan2⁡x21+tan2⁡x=1+tan2⁡x=1+(2−3)2=8−43=4(2−3)=432−122=443−1222=16sin2⁡π12

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