f:R†→R be a continuous function satisfying fxy=f(x)−f(y)∀x,y∈R+.If f′(1)=1, then
f is unbounded
limx→0 f1x=0
limx→0 f(1+x)x=1
limx→0 x⋅f(x)=0
f′(x)=limh→0 f(x+h)−f(x)h=limh→0 f1+hxhxx=f′(1)x=1x⇒f(x)=lnx as f(1)=0