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f:R→R be a mapping defined by f(x)=x3+5, then f−1(x)=

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a

(x+5)13

b

(x−5)13

c

(5−x)13

d

5−x

answer is B.

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Detailed Solution

f−1(x)=y⇒x=f(y)⇒x=y3+5⇒y3=x−5⇒y=(x−5)13 ⇒f−1(x)=(x−5)13

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