First slide
Functions (XII)
Question

f:RR  fx2+x+3+2fx23x+5=6x210x+17 xR then the value of f(100) is 

Moderate
Solution

 obviously f is a linear polynomial    (Since degree of LHS and RHS is same)

letf(x)=ax+b hence fx2+x+3+2fx23x+56x210x+17ax2+x+3+b+2ax23x+5+b6x210x+17comparing coeff of x2 and coeff. of x a+2a=6......(1) a6a=10......(2)   a=2comparing constants 3a+b+10a+2b=17 6+b+20+2b=17 b=3 f(x)=2x3f(100)=197

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