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f:R→R, g:R→R two functions defined by f(x)=x+12,g(x)=3x−2 then (f−1og−1)(4)=

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a

1

b

2

c

3

d

4

answer is C.

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Detailed Solution

f(x)=x+12g(x)=3x-2 f-1(x)=2x-1, g-1(x)=x+23 ⇒(f−1og−1)(x)=2x+13 (f−1og−1)(4)=2(4)+13=93=3

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f:R→R, g:R→R two functions defined by f(x)=x+12,g(x)=3x−2 then (f−1og−1)(4)=