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$f (x) = 2 + \cos^{2} x + \sec^{2} x its value always$

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fx<1

fx=1

27fx>1

fx≥4

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detailed solution

Correct option is D

We havecos2x+sec2x2≥cos2xsec2x ∵AM≥GM⇒cos2x+sec2x≥2∴f(x)≥4

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f(x)=2+cos2x+sec2x its value always

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$f (x) = 2 + \cos^{2} x + \sec^{2} x its value always$