f(x)=limn→∞(x−1)2n−1(x−1)2n+1 is discontinuous at
x = 0 only
x = 2 only
x = 0 and 2
x = 0, 1,2 only
f(x) is discontinuous when x = 0,2 f(x)=limn→∞1−1[(x−1)2]n1+1[(x−1)2]n =1,x<00,x=0−1,0<x<20,x=21,x>2
Thus, f(x) is discontinuous at x = 0,2.