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Q.

f(x)=log(1+x1−x) satisfies the equation f(x1)+f(x2)=

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a

f(x1+x21+x1x2)

b

f(x1+x21−x1x2)

c

f(x1−x21+x1x2)

d

f(x1 x2 )

answer is A.

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Detailed Solution

f(x)=log(1+x1−x)       now       f(x1)+f(x2)=log(1+x11−x1)+log(1+x21−x2)            =log[1+x11−x1.1+x21−x2]                = log1+x1x2 +x1+x21+x1x2-x1+x2 =log1+x1+x21+x1x21-x1+x21+x1x2            =f(x1+x21+x1x2)
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