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$f (x) = \min {\sin x, \cos x} i n [0, \frac{π}{4}] then f^{'} (0) =$

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Correct option is A

We have fx=minsinx,cosx in 0,π4 ⇒⇒:f(x)=sinxf'(x)=cosx⇒f'(0)=1

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f(x)=min{sinx,cosx} in 0,π4 then f'(0)=

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Ready to Test Your Skills?

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$f (x) = \min {\sin x, \cos x} i n [0, \frac{π}{4}] then f^{'} (0) =$