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fx=Sce11+Cos2x where. is g.i.f.  Then range of fx=

a
π4,π3
b
0,π2
c
π4,π2
d
0,π3

detailed solution

Correct option is D

We know that 0≤cos2x≤1.⇒1≤1+cos2x≤2So  1+cos2x= either 1 or 2⇒Sec−11+cos2x=Sec-11 or Sec-12                                     =0 orπ3 ∴range of fx=0,π3

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