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Q.

f(x)=sinax2x2,x≠034+14a,x=0 for what values of a, f(x) is continuous at x = 0

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a

14, −1

b

14, 1

c

1, −14

d

−1, −14

answer is C.

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Detailed Solution

x→0Lt f(x)=f(0) x→0Lt sinax2x2=34+14a x→0Lt sinax2ax2×a=34+14a ⇒a=34+14a⇒4a2-3a-1=0⇒a=−1/4, 1

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