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$f (x) = x [3 - \log (\frac{\sin x}{x})] - 2 to be continuous at x = 0 then f (0) =$

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detailed solution

Correct option is C

Ltx→0 fx=Ltx→0 3x−xlogsinxx−2=−2=f0∴f0=−2

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f(x)=x3−log⁡sin⁡xx−2 to be continuous at x=0 then f(0)=

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$f (x) = x [3 - \log (\frac{\sin x}{x})] - 2 to be continuous at x = 0 then f (0) =$