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Q.

f(x)=3x2sin⁡2x2 if x<0x2+2x+c1−3x2 if x≥0,x≠13 then in order that f be continuous at x=0 then 0 if x=13the value of c is

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a

2

b

4

c

6

d

8

answer is C.

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Detailed Solution

Ltx=0−  fx=Ltx=0−  3x2sin2x2=6 Ltx→0  sin2x22x2=6Ltx=0+  fx=Ltx=0+  x2+2x+c1−3x2=c1=c∴f is continuous  ∴c=6
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